Problem 예제.

Views 272 • Comments 0 • Last Updated at 1 year ago Full screen  
  • 그리기
  • 근궤적 그리기

G(s)H(s)=k(s+1)s(s+4)(s2+2s+2)G(s)H(s)=\dfrac{k(s+1)}{s(s+4)(s^2+2s+2)}로 주어질 때 특성 방정식 1+G(s)H(s)=01+G(s)H(s)=0의 점근선의 각도와 교차점을 구하면?

Subscribe to see the correct answer.
1

σo=75,βo=45,180,315\sigma_o = - \dfrac{7}{5}, \beta_o = 45^\circ, 180^\circ, 315^\circ

2

σo=73,βo=60,180,300\sigma_o = - \dfrac{7}{3}, \beta_o = 60^\circ, 180^\circ, 300^\circ

3

σo=53,βo=60,180,300\sigma_o = - \dfrac{5}{3}, \beta_o = 60^\circ, 180^\circ, 300^\circ

4

σo=53,βo=45,180,315\sigma_o = - \dfrac{5}{3}, \beta_o = 45^\circ, 180^\circ, 315^\circ

previous article
next article