근궤적 기법

Problem 예제.

Multiple Choice • Views 709 • Comments 0 • Last Updated at 4 months ago  
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G(s)H(s)=k(s+1)s(s+4)(s2+2s+2)G(s)H(s)=\dfrac{k(s+1)}{s(s+4)(s^2+2s+2)}로 주어질 때 특성 방정식 1+G(s)H(s)=01+G(s)H(s)=0의 점근선의 각도와 교차점을 구하면?

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1

σo=−75,βo=45∘,180∘,315∘\sigma_o = - \dfrac{7}{5}, \beta_o = 45^\circ, 180^\circ, 315^\circ

2

σo=−53,βo=45∘,180∘,315∘\sigma_o = - \dfrac{5}{3}, \beta_o = 45^\circ, 180^\circ, 315^\circ

3

σo=−53,βo=60∘,180∘,300∘\sigma_o = - \dfrac{5}{3}, \beta_o = 60^\circ, 180^\circ, 300^\circ

4

σo=−73,βo=60∘,180∘,300∘\sigma_o = - \dfrac{7}{3}, \beta_o = 60^\circ, 180^\circ, 300^\circ

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