Problem 예제.

Views 111 • Comments 0 • Last Updated at 1 year ago Full screen  
  • 안정도
  • 상태변수방정식

다음 계통의 고유값을 구하면?

[X˙1X˙2X˙3]=[0103021276][X1X2X3] \begin{bmatrix} \dot X_1\\ \dot X_2 \\ \dot X_3 \end{bmatrix} = \begin{bmatrix} 0 & 1 & 0 \\ 3 & 0 & 2 \\ -12 & -7 & -6 \end{bmatrix} \begin{bmatrix} X_1\\ X_2 \\ X_3 \end{bmatrix}

Subscribe to see the correct answer.
1

λ1=1,λ2=3,λ3=5 \lambda_1 = -1, \quad \lambda_2 =-3, \quad \lambda_3 = -5

2

λ1=0,λ2=2,λ3=3 \lambda_1 = 0, \quad \lambda_2 =-2, \quad \lambda_3 = -3

3

λ1=1,λ2=2,λ3=3 \lambda_1 = -1, \quad \lambda_2 =-2, \quad \lambda_3 = -3

4

λ1=0,λ2=3,λ3=5 \lambda_1 = 0, \quad \lambda_2 =-3, \quad \lambda_3 = -5

previous article
next article